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(-(x^2)/2)-2x-5/2=0
We get rid of parentheses
-x^2/2-2x-5/2=0
We multiply all the terms by the denominator
-x^2-2x*2-5=0
We add all the numbers together, and all the variables
-1x^2-2x*2-5=0
Wy multiply elements
-1x^2-4x-5=0
a = -1; b = -4; c = -5;
Δ = b2-4ac
Δ = -42-4·(-1)·(-5)
Δ = -4
Delta is less than zero, so there is no solution for the equation
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